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Re: [PVS-Help] R_pred



Why should it work ? What is the definition of R?  For an arbitrary R,
the fact that R(x) and R(y) hold doesn't imply that R(x+y) holds. Take
R=odd? for example.


Jerome wrote:
> I have the following:
> 
>    [-1]  W(root, j!1) >= 0
>    [-2]  R_pred(W(root, j!1))
>    [-3]  distance(s!1)(root) >= 0
>    [-4]  R_pred(distance(s!1)(root))
>      |-------
>    [1]   R_pred(distance(s!1)(root) + W(root, j!1))
> 
> Why is "assert" not an adequate means of discharging? What am I
> missing? Thanks
> 
> jerome
> 
> 

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Cesar A. Munoz H., Senior Staff Scientist     mailto:munoz@xxxxxxxxxx
National Institute of Aerospace         mailto:Cesar.A.Munoz@xxxxxxxx
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