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Re: [PVS-Help] R_pred
Why should it work ? What is the definition of R? For an arbitrary R,
the fact that R(x) and R(y) hold doesn't imply that R(x+y) holds. Take
R=odd? for example.
Jerome wrote:
> I have the following:
>
> [-1] W(root, j!1) >= 0
> [-2] R_pred(W(root, j!1))
> [-3] distance(s!1)(root) >= 0
> [-4] R_pred(distance(s!1)(root))
> |-------
> [1] R_pred(distance(s!1)(root) + W(root, j!1))
>
> Why is "assert" not an adequate means of discharging? What am I
> missing? Thanks
>
> jerome
>
>
--
Cesar A. Munoz H., Senior Staff Scientist mailto:munoz@xxxxxxxxxx
National Institute of Aerospace mailto:Cesar.A.Munoz@xxxxxxxx
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